|

CMT
program


| |
| Overview
Thirty small wood specimens are tested in compression to failure and failure
loads are recorded. The data is statistically analyzed to illustrate
variability of wood. |
 |
|
Prelab assignment |
Four typical 3-in. long specimens Objectives:
-
Demonstration of material strength variability with a highly variable
material
-
Practice with the measurement and testing equipment
-
Practice data processing and manipulation with Microsoft Excel
Data Analysis
Using Microsoft Excel
-
The fun of destructive testing.
|
|

Safety Info |
Safety!
Safety glasses are required at all times while equipment is turned on. Not
only are safety glasses a good precaution, they prepare students for industry where they
are also required.
Face shields should be used when working close to failing specimens
|
 |
Equipment
Used
Procedure
[excel data sheets]
right-click, save target as
Each of the 30 specimens will be tested in compression, parallel to the
grain, until failure.
- Before leaving your table, number specimens from 1 to 30, measure and record dimensions
with dial calipers. Enter
data in Table 1-1.
- Use either the Instron 4400R or
Instron 4485 machine. At the testing machine,
verify load application speed of 0.25 inches/minute.
- Place the specimen in the testing machine and apply load until failure.
Hint:
Get the
names, email addresses and phone numbers of the students in your lab group, as well as your TA.
Use FirstClass email to send data to everyone and distribute contact
information.
|
 |
Data
Development of Results Include the following in the results section of your
report: [see the videos on how to do it in MS
Excel] [detailed written instructions on how to do it in MS
Excel]
- Compute the stress at failure (s , in psi) for each
specimen.
The
stress at failure equals the load at failure (L, in lbs.) divided by the
specimen's
cross-sectional area (A, in in2), thus:
s = L /A
- Give the range (minimum and maximum) of failure stresses.
- Compute the mean of the failure stresses.
Rm
= (R1+R2+R3+ ...... + R30)/30
Rm = mean failure stress
R1 - R30 (Ri) are the individual failure
stresses.
- Using Table 1-1,
compute the standard deviation and coefficient of variation of the failure stresses.
Standard deviation =

in which n = sample size = 30 data points
Coefficient of variation = (Standard deviation)/Rm
- Complete Table 1-2 to create the data to plot the histogram
a. In the first column list failure stresses (Ri) sorted
from lowest (top) to highest (bottom).
Calculate a suitable number of intervals (whole number larger than the equation below
generates) for the data range for plotting a histogram.
# intervals = 1+3.3 x log(n), say 6
Divide the range of Failure Stress data by the # of intervals and round to a nice
even interval size number (like 500 lbs.)
interval size = (max fail stress - min fail stress) / # intervals
Create a table of Interval and Frequency data.
The interval
is a label (like 2500 - 3000 lbs.).
Frequency is the number of
Failure Stresses that occur within that interval - just count them manually.
- Plot a histogram of your results.

|
 |
Reference
American Forest and Paper Association. 2001. Supplement NDS National Design
Specification for Wood Construction. American Wood Council.
|
|